(7r+4)(r^2-5r-50)=0

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Solution for (7r+4)(r^2-5r-50)=0 equation: 


Simplifying
(7r + 4)(r2 + -5r + -50) = 0

Reorder the terms:
(4 + 7r)(r2 + -5r + -50) = 0

Reorder the terms:
(4 + 7r)(-50 + -5r + r2) = 0

Multiply (4 + 7r) * (-50 + -5r + r2)
(4(-50 + -5r + r2) + 7r * (-50 + -5r + r2)) = 0
((-50 * 4 + -5r * 4 + r2 * 4) + 7r * (-50 + -5r + r2)) = 0
((-200 + -20r + 4r2) + 7r * (-50 + -5r + r2)) = 0
(-200 + -20r + 4r2 + (-50 * 7r + -5r * 7r + r2 * 7r)) = 0
(-200 + -20r + 4r2 + (-350r + -35r2 + 7r3)) = 0

Reorder the terms:
(-200 + -20r + -350r + 4r2 + -35r2 + 7r3) = 0

Combine like terms: -20r + -350r = -370r
(-200 + -370r + 4r2 + -35r2 + 7r3) = 0

Combine like terms: 4r2 + -35r2 = -31r2
(-200 + -370r + -31r2 + 7r3) = 0

Solving
-200 + -370r + -31r2 + 7r3 = 0

Solving for variable 'r'.

The solution to this equation could not be determined.

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